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Sunday, March 11, 2018

Palindrome Checker C#

static bool isPalindrome(string word)
{
    string rword = "";
 
    foreach (var c in word)
        rword = c + rword;
 
    return rword.ToUpper() == word.ToUpper() ? true : false ;
 
}

Monday, September 23, 2013

TogetherJS



TogetherJS gives you a capability to add collaboration tool to your website.

Saturday, January 16, 2010

My Fizz Buzz Solution

My Fizz Buzz Solution

Solution 1: Using Ternary Operator
            for (int i = 1; i < 101; i++)
            {
                string result = "";
                result = i % 3 == 0 ? "Fizz" : ""// check if i is divisible by 3
                result += i % 5 == 0 ? "Buzz" : "";// check if i is divisible by 5
                Console.Write("\n" + i.ToString() + " - " + result);
            }

Solution 2: Using IF Operator
            for (int i = 1; i < 101; i++)
            {
                string result = "";
                if (i % 3 == 0// check if i is divisible by 3
                {
                    //give result the value fizz
                    result = "Fizz"
                }
                if (i % 5 == 0// check if i is divisible by 5
                {
                    //gets the value of result and add to the buzz value giving an output of fizz or fizzbuzz
                    result += "Buzz"
                }
                //show result;
                Console.Write(" \n" + i.ToString() + " - " + result);
            }

Sunday, July 19, 2009

Fabonacci Function c#










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static void fibonacci(int x)
{
int y = 0, z = 1, total;

for (int i = 0; i < x; i++)
{
total = y + z;
Console.WriteLine(total);
y = z;
z = total;

}
}

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